How to convert joules per kilogram kelvin to BTU per pound °F
BTU/(lb⋅°F) = J/(kg⋅K) × 0.0002388458966Because one BTU per pound °F equals 4,186.8 joules per kilogram kelvin, you can also divide: BTU/(lb⋅°F) = J/(kg⋅K) ÷ 4,186.8.
A joule per kilogram kelvin is smaller than a BTU per pound °F: it takes 4,186.8 joules per kilogram kelvin to make one BTU per pound °F.
Worked examples
- 1 joule per kilogram kelvin1 J/(kg⋅K) × 0.0002388458966 = 0.0002388458966 BTU/(lb⋅°F)
- 5 joules per kilogram kelvin5 J/(kg⋅K) × 0.0002388458966 = 0.001194229483 BTU/(lb⋅°F)
- 10 joules per kilogram kelvin10 J/(kg⋅K) × 0.0002388458966 = 0.002388458966 BTU/(lb⋅°F)
- 20 joules per kilogram kelvin20 J/(kg⋅K) × 0.0002388458966 = 0.004776917933 BTU/(lb⋅°F)
- 100 joules per kilogram kelvin100 J/(kg⋅K) × 0.0002388458966 = 0.02388458966 BTU/(lb⋅°F)
Joules per kilogram kelvin to BTU per pound °F conversion table
Values are calculated by the conversion engine and rounded to 8 significant figures.
| Joules per kilogram kelvin (J/(kg⋅K)) | BTU per pound °F (BTU/(lb⋅°F)) |
|---|---|
| 0.1 J/(kg⋅K) | 0.00002388459 BTU/(lb⋅°F) |
| 0.25 J/(kg⋅K) | 0.000059711474 BTU/(lb⋅°F) |
| 0.5 J/(kg⋅K) | 0.00011942295 BTU/(lb⋅°F) |
| 1 J/(kg⋅K) | 0.0002388459 BTU/(lb⋅°F) |
| 2 J/(kg⋅K) | 0.00047769179 BTU/(lb⋅°F) |
| 3 J/(kg⋅K) | 0.00071653769 BTU/(lb⋅°F) |
| 4 J/(kg⋅K) | 0.00095538359 BTU/(lb⋅°F) |
| 5 J/(kg⋅K) | 0.0011942295 BTU/(lb⋅°F) |
| 6 J/(kg⋅K) | 0.0014330754 BTU/(lb⋅°F) |
| 7 J/(kg⋅K) | 0.0016719213 BTU/(lb⋅°F) |
| 8 J/(kg⋅K) | 0.0019107672 BTU/(lb⋅°F) |
| 9 J/(kg⋅K) | 0.0021496131 BTU/(lb⋅°F) |
| 10 J/(kg⋅K) | 0.002388459 BTU/(lb⋅°F) |
| Joules per kilogram kelvin (J/(kg⋅K)) | BTU per pound °F (BTU/(lb⋅°F)) |
|---|---|
| 12 J/(kg⋅K) | 0.0028661508 BTU/(lb⋅°F) |
| 15 J/(kg⋅K) | 0.0035826884 BTU/(lb⋅°F) |
| 20 J/(kg⋅K) | 0.0047769179 BTU/(lb⋅°F) |
| 25 J/(kg⋅K) | 0.0059711474 BTU/(lb⋅°F) |
| 30 J/(kg⋅K) | 0.0071653769 BTU/(lb⋅°F) |
| 40 J/(kg⋅K) | 0.0095538359 BTU/(lb⋅°F) |
| 50 J/(kg⋅K) | 0.011942295 BTU/(lb⋅°F) |
| 75 J/(kg⋅K) | 0.017913442 BTU/(lb⋅°F) |
| 100 J/(kg⋅K) | 0.02388459 BTU/(lb⋅°F) |
| 250 J/(kg⋅K) | 0.059711474 BTU/(lb⋅°F) |
| 500 J/(kg⋅K) | 0.11942295 BTU/(lb⋅°F) |
| 1,000 J/(kg⋅K) | 0.2388459 BTU/(lb⋅°F) |
About the units
Joule per kilogram kelvin (J/(kg⋅K))
The joule per kilogram kelvin (J/(kg⋅K)) is a unit of specific heat capacity in the International System of Units (SI).
BTU per pound °F (BTU/(lb⋅°F))
With the International Table BTU this is exactly 4,186.8 J/(kg·K).
Frequently asked questions
How many BTU per pound °F are in one joule per kilogram kelvin?
There are 0.0002388458966 BTU per pound °F in one joule per kilogram kelvin, and this value is exact by definition.
How do I convert joules per kilogram kelvin to BTU per pound °F?
Multiply the number of joules per kilogram kelvin by 0.0002388458966. For example, 10 J/(kg⋅K) × 0.0002388458966 = 0.002388458966 BTU/(lb⋅°F).
How many joules per kilogram kelvin are in one BTU per pound °F?
One BTU per pound °F equals 4,186.8 joules per kilogram kelvin. That is the reverse factor, 1 ÷ 0.0002388458966.
What is 10 joules per kilogram kelvin in BTU per pound °F?
10 J/(kg⋅K) = 0.002388458966 BTU/(lb⋅°F).
Is this J/(kg⋅K) to BTU/(lb⋅°F) converter accurate?
Yes. Both units are defined exactly in terms of SI units, so the conversion factor is exact; results are shown to 12 significant figures by default and you can change precision in the converter. Calculations run in your browser using the same tested engine that generated this page.