How to convert joules per kilogram kelvin to calories per gram °C
cal/(g⋅°C) = J/(kg⋅K) × 0.0002390057361Because one calorie per gram °C equals 4,184 joules per kilogram kelvin, you can also divide: cal/(g⋅°C) = J/(kg⋅K) ÷ 4,184.
A joule per kilogram kelvin is smaller than a calorie per gram °C: it takes 4,184 joules per kilogram kelvin to make one calorie per gram °C.
Worked examples
- 1 joule per kilogram kelvin1 J/(kg⋅K) × 0.0002390057361 = 0.0002390057361 cal/(g⋅°C)
- 5 joules per kilogram kelvin5 J/(kg⋅K) × 0.0002390057361 = 0.001195028681 cal/(g⋅°C)
- 10 joules per kilogram kelvin10 J/(kg⋅K) × 0.0002390057361 = 0.002390057361 cal/(g⋅°C)
- 20 joules per kilogram kelvin20 J/(kg⋅K) × 0.0002390057361 = 0.004780114723 cal/(g⋅°C)
- 100 joules per kilogram kelvin100 J/(kg⋅K) × 0.0002390057361 = 0.02390057361 cal/(g⋅°C)
Joules per kilogram kelvin to calories per gram °C conversion table
Values are calculated by the conversion engine and rounded to 8 significant figures.
| Joules per kilogram kelvin (J/(kg⋅K)) | Calories per gram °C (cal/(g⋅°C)) |
|---|---|
| 0.1 J/(kg⋅K) | 0.000023900574 cal/(g⋅°C) |
| 0.25 J/(kg⋅K) | 0.000059751434 cal/(g⋅°C) |
| 0.5 J/(kg⋅K) | 0.00011950287 cal/(g⋅°C) |
| 1 J/(kg⋅K) | 0.00023900574 cal/(g⋅°C) |
| 2 J/(kg⋅K) | 0.00047801147 cal/(g⋅°C) |
| 3 J/(kg⋅K) | 0.00071701721 cal/(g⋅°C) |
| 4 J/(kg⋅K) | 0.00095602294 cal/(g⋅°C) |
| 5 J/(kg⋅K) | 0.0011950287 cal/(g⋅°C) |
| 6 J/(kg⋅K) | 0.0014340344 cal/(g⋅°C) |
| 7 J/(kg⋅K) | 0.0016730402 cal/(g⋅°C) |
| 8 J/(kg⋅K) | 0.0019120459 cal/(g⋅°C) |
| 9 J/(kg⋅K) | 0.0021510516 cal/(g⋅°C) |
| 10 J/(kg⋅K) | 0.0023900574 cal/(g⋅°C) |
| Joules per kilogram kelvin (J/(kg⋅K)) | Calories per gram °C (cal/(g⋅°C)) |
|---|---|
| 12 J/(kg⋅K) | 0.0028680688 cal/(g⋅°C) |
| 15 J/(kg⋅K) | 0.003585086 cal/(g⋅°C) |
| 20 J/(kg⋅K) | 0.0047801147 cal/(g⋅°C) |
| 25 J/(kg⋅K) | 0.0059751434 cal/(g⋅°C) |
| 30 J/(kg⋅K) | 0.0071701721 cal/(g⋅°C) |
| 40 J/(kg⋅K) | 0.0095602294 cal/(g⋅°C) |
| 50 J/(kg⋅K) | 0.011950287 cal/(g⋅°C) |
| 75 J/(kg⋅K) | 0.01792543 cal/(g⋅°C) |
| 100 J/(kg⋅K) | 0.023900574 cal/(g⋅°C) |
| 250 J/(kg⋅K) | 0.059751434 cal/(g⋅°C) |
| 500 J/(kg⋅K) | 0.11950287 cal/(g⋅°C) |
| 1,000 J/(kg⋅K) | 0.23900574 cal/(g⋅°C) |
About the units
Joule per kilogram kelvin (J/(kg⋅K))
The joule per kilogram kelvin (J/(kg⋅K)) is a unit of specific heat capacity in the International System of Units (SI).
Calorie per gram °C (cal/(g⋅°C))
The calorie per gram °C (cal/(g⋅°C)) is a unit of specific heat capacity. One calorie per gram °C equals 4,184 joules per kilogram kelvin (J/(kg⋅K)).
Frequently asked questions
How many calories per gram °C are in one joule per kilogram kelvin?
There are 0.0002390057361 calories per gram °C in one joule per kilogram kelvin, and this value is exact by definition.
How do I convert joules per kilogram kelvin to calories per gram °C?
Multiply the number of joules per kilogram kelvin by 0.0002390057361. For example, 10 J/(kg⋅K) × 0.0002390057361 = 0.002390057361 cal/(g⋅°C).
How many joules per kilogram kelvin are in one calorie per gram °C?
One calorie per gram °C equals 4,184 joules per kilogram kelvin. That is the reverse factor, 1 ÷ 0.0002390057361.
What is 10 joules per kilogram kelvin in calories per gram °C?
10 J/(kg⋅K) = 0.002390057361 cal/(g⋅°C).
Is this J/(kg⋅K) to cal/(g⋅°C) converter accurate?
Yes. Both units are defined exactly in terms of SI units, so the conversion factor is exact; results are shown to 12 significant figures by default and you can change precision in the converter. Calculations run in your browser using the same tested engine that generated this page.