How to convert BTU per pound °F to joules per kilogram kelvin
J/(kg⋅K) = BTU/(lb⋅°F) × 4,186.8Multiply the value in BTU per pound °F by 4,186.8. To go the other way, multiply by 0.0002388458966 (or divide by 4,186.8).
A BTU per pound °F is larger than a joule per kilogram kelvin: one BTU per pound °F contains 4,186.8 joules per kilogram kelvin.
Worked examples
- 1 BTU per pound °F1 BTU/(lb⋅°F) × 4,186.8 = 4,186.8 J/(kg⋅K)
- 5 BTU per pound °F5 BTU/(lb⋅°F) × 4,186.8 = 20,934 J/(kg⋅K)
- 10 BTU per pound °F10 BTU/(lb⋅°F) × 4,186.8 = 41,868 J/(kg⋅K)
- 20 BTU per pound °F20 BTU/(lb⋅°F) × 4,186.8 = 83,736 J/(kg⋅K)
- 100 BTU per pound °F100 BTU/(lb⋅°F) × 4,186.8 = 418,680 J/(kg⋅K)
BTU per pound °F to joules per kilogram kelvin conversion table
Values are calculated by the conversion engine and rounded to 8 significant figures.
| BTU per pound °F (BTU/(lb⋅°F)) | Joules per kilogram kelvin (J/(kg⋅K)) |
|---|---|
| 0.1 BTU/(lb⋅°F) | 418.68 J/(kg⋅K) |
| 0.25 BTU/(lb⋅°F) | 1,046.7 J/(kg⋅K) |
| 0.5 BTU/(lb⋅°F) | 2,093.4 J/(kg⋅K) |
| 1 BTU/(lb⋅°F) | 4,186.8 J/(kg⋅K) |
| 2 BTU/(lb⋅°F) | 8,373.6 J/(kg⋅K) |
| 3 BTU/(lb⋅°F) | 12,560.4 J/(kg⋅K) |
| 4 BTU/(lb⋅°F) | 16,747.2 J/(kg⋅K) |
| 5 BTU/(lb⋅°F) | 20,934 J/(kg⋅K) |
| 6 BTU/(lb⋅°F) | 25,120.8 J/(kg⋅K) |
| 7 BTU/(lb⋅°F) | 29,307.6 J/(kg⋅K) |
| 8 BTU/(lb⋅°F) | 33,494.4 J/(kg⋅K) |
| 9 BTU/(lb⋅°F) | 37,681.2 J/(kg⋅K) |
| 10 BTU/(lb⋅°F) | 41,868 J/(kg⋅K) |
| BTU per pound °F (BTU/(lb⋅°F)) | Joules per kilogram kelvin (J/(kg⋅K)) |
|---|---|
| 12 BTU/(lb⋅°F) | 50,241.6 J/(kg⋅K) |
| 15 BTU/(lb⋅°F) | 62,802 J/(kg⋅K) |
| 20 BTU/(lb⋅°F) | 83,736 J/(kg⋅K) |
| 25 BTU/(lb⋅°F) | 104,670 J/(kg⋅K) |
| 30 BTU/(lb⋅°F) | 125,604 J/(kg⋅K) |
| 40 BTU/(lb⋅°F) | 167,472 J/(kg⋅K) |
| 50 BTU/(lb⋅°F) | 209,340 J/(kg⋅K) |
| 75 BTU/(lb⋅°F) | 314,010 J/(kg⋅K) |
| 100 BTU/(lb⋅°F) | 418,680 J/(kg⋅K) |
| 250 BTU/(lb⋅°F) | 1,046,700 J/(kg⋅K) |
| 500 BTU/(lb⋅°F) | 2,093,400 J/(kg⋅K) |
| 1,000 BTU/(lb⋅°F) | 4,186,800 J/(kg⋅K) |
About the units
BTU per pound °F (BTU/(lb⋅°F))
With the International Table BTU this is exactly 4,186.8 J/(kg·K).
Joule per kilogram kelvin (J/(kg⋅K))
The joule per kilogram kelvin (J/(kg⋅K)) is a unit of specific heat capacity in the International System of Units (SI).
Frequently asked questions
How many joules per kilogram kelvin are in one BTU per pound °F?
There are 4,186.8 joules per kilogram kelvin in one BTU per pound °F, and this value is exact by definition.
How do I convert BTU per pound °F to joules per kilogram kelvin?
Multiply the number of BTU per pound °F by 4,186.8. For example, 10 BTU/(lb⋅°F) × 4,186.8 = 41,868 J/(kg⋅K).
How many BTU per pound °F are in one joule per kilogram kelvin?
One joule per kilogram kelvin equals 0.0002388458966 BTU per pound °F. That is the reverse factor, 1 ÷ 4,186.8.
What is 10 BTU per pound °F in joules per kilogram kelvin?
10 BTU/(lb⋅°F) = 41,868 J/(kg⋅K).
Is this BTU/(lb⋅°F) to J/(kg⋅K) converter accurate?
Yes. Both units are defined exactly in terms of SI units, so the conversion factor is exact; results are shown to 12 significant figures by default and you can change precision in the converter. Calculations run in your browser using the same tested engine that generated this page.